document.write( "Question 135988: Please help with this question. Determine the area of the triangle to the nearest tenth. Use A=bh/2. It is a right triangle 30-60-90 and the base measure is 6squareroot3. The height is not given. Thank you \n" ); document.write( "
Algebra.Com's Answer #99643 by nycsharkman(136)![]() ![]() ![]() You can put this solution on YOUR website! Please help with this question. Determine the area of the triangle to the nearest tenth. Use A=bh/2. It is a right triangle 30-60-90 and the base measure is 6squareroot3. The height is not given. \r \n" ); document.write( "\n" ); document.write( "Area = base times height divided by 2\r \n" ); document.write( "\n" ); document.write( "It's a 30-60-90 triangle.\r \n" ); document.write( "\n" ); document.write( "In this type of triangle, 30 degrees is opposite a, 90 degrees is opposite 2a and 60 degrees is opposite a times the square root 3, which is written a(sqrt{3}). The value of a here is the number 6 in front of square root 3 in the given base.\r \n" ); document.write( "\n" ); document.write( "The base is 6(sqrt{3}), which tells me the value of a is 6.\r \n" ); document.write( "\n" ); document.write( "Since 30 degrees is opposite the height of the triangle and a = 6, then the height is 6.\r \n" ); document.write( "\n" ); document.write( "A = [6(sqrt{3}) times 6]/2\r \n" ); document.write( "\n" ); document.write( "A = 36(sqrt{3})/2\r \n" ); document.write( "\n" ); document.write( "A = 18(sqrt{3})\r \n" ); document.write( "\n" ); document.write( "Is this clear?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |