document.write( "Question 135987: A rectangular piece of cardboard is to be formed into an uncovered box. The piece of cardboard is 2 cm longer than it is wide. A square that measures 3 cm on a side is cut from each corner. When the sides are turned up to form a box, its volume is 765 cubic cm. Find the dimensions in cm of the original piece of cardboard. \n" ); document.write( "
Algebra.Com's Answer #99630 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
LENGTH=X+2
\n" ); document.write( "WIDTH=X
\n" ); document.write( "AFTER CUTING THE 3CM SQUARE OUT OF THE CORNERS WE HAVE THE LENGTH=(X+2-6)
\n" ); document.write( "WIDTH=(X-6)
\n" ); document.write( "HEIGHT=3
\n" ); document.write( "765=3(X-6)(X+2-6)
\n" ); document.write( "765=(3X-18)(X-4)
\n" ); document.write( "765=3X^2-18X-12X+72
\n" ); document.write( "3X^2-30X+72-765=0
\n" ); document.write( "3X^2-30X-693=0
\n" ); document.write( "3(X^2-10X-231)=0
\n" ); document.write( "(X-21)(X+11)=0
\n" ); document.write( "X-21=0
\n" ); document.write( "X=21 ANSWER FOR THWE WIDTH.
\n" ); document.write( "21+2=23 ANSWER FOR THE LENGTH.
\n" ); document.write( "PROOF
\n" ); document.write( "3(21-6)(23-6)=765
\n" ); document.write( "3*15*17=765
\n" ); document.write( "765=765\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );