document.write( "Question 135923: A & B working together can do a job for 10 days.If each works alone A takes 5 days longer than B to do the job.How long will it take each one of them to do the job. \n" ); document.write( "
Algebra.Com's Answer #99587 by ptaylor(2198)\"\" \"About 
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\n" ); document.write( "Let x= amount of time in days that it takes B to do the job working alone\r
\n" ); document.write( "\n" ); document.write( "B, then, works at the rate of 1/x of the job per day
\n" ); document.write( "x+5=amount of time in days that it takes A working alone
\n" ); document.write( "A, then, works at the rate of 1/(x+5) of the job per day\r
\n" ); document.write( "\n" ); document.write( "Together A&B works at the rate of 1/x + 1/(x+5)=(x+5+x)/x(x+5)=
\n" ); document.write( "(2x+5)/x(x+5) of the job per day, we are told that, working together, it takes them 10 days so our equation to solve is\r
\n" ); document.write( "\n" ); document.write( "((2x+5)/x(x+5))*10=1 (1 job, that is) multiply each term by x(x+5)
\n" ); document.write( "10(2x+5)=x(x+5)
\n" ); document.write( "20x+50=x^2+5x subtract 20x and 50 from each side\r
\n" ); document.write( "\n" ); document.write( "x^2-15x-50=0 quadratic in standard form; solve using the quadratic formula\r
\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "\"x+=+%2815+%2B-+sqrt%28+225%2B200+%29%29%2F%282%29+\"
\n" ); document.write( "\"x+=+%2815+%2B-+20.616%29%2F%282%29+\"
\n" ); document.write( "\"x+=+%2815+%2B20.616%29%2F%282%29+\"
\n" ); document.write( "\"x+=+17.808\" days ---------------------amount of time needed by B working alone
\n" ); document.write( "17.808+5=22.808----------------------------amount of time needed by A working alone\r
\n" ); document.write( "\n" ); document.write( "FORGET THE NEGATIVE VALUE FOR x, TIME WOULD BE POSITIVE IN THIS CASE\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "(1/17.808)+(1/22.808)=1/10\r
\n" ); document.write( "\n" ); document.write( "0.05615+0.0438=0.1
\n" ); document.write( "0.099999~~~~~~0.1\r
\n" ); document.write( "\n" ); document.write( "Hope this helps ------ptaylor\r
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