document.write( "Question 135783: three times a number increades 5 times another number is 49 but twice the second number exceeds 5 times the first number by 1.what are the numbers? \n" ); document.write( "
Algebra.Com's Answer #99564 by ankor@dixie-net.com(22740)\"\" \"About 
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Let x = \"a number\"
\n" ); document.write( "Let y = \"another number\"
\n" ); document.write( ":
\n" ); document.write( "Write an equation for each statement:
\n" ); document.write( ":
\n" ); document.write( "\"three times a number increased 5 times another number is 49\"
\n" ); document.write( "3x + 5y = 49
\n" ); document.write( ":
\n" ); document.write( "\"twice the second number exceeds 5 times the first number by 1.\"
\n" ); document.write( "2y = 5x + 1
\n" ); document.write( "In standard form
\n" ); document.write( "-5x + 2y = 1
\n" ); document.write( ":
\n" ); document.write( "what are the numbers?
\n" ); document.write( ":
\n" ); document.write( "Multiply the 1st equation by 5, and the 2nd equation by 3
\n" ); document.write( " 15x + 25y = 245
\n" ); document.write( "-15x + 6y = 3
\n" ); document.write( "-----------------Adding eliminates, x; find y:
\n" ); document.write( " 0x + 31y = 248
\n" ); document.write( ":
\n" ); document.write( "y = \"248%2F31\"
\n" ); document.write( "y = 8
\n" ); document.write( ":
\n" ); document.write( "Find x using the 1st equation
\n" ); document.write( "3x + 5(8) = 49
\n" ); document.write( "3x = 49 - 40
\n" ); document.write( "x = \"9%2F3\"
\n" ); document.write( "x = 3
\n" ); document.write( ":
\n" ); document.write( "Check solutions in the 2nd equation:
\n" ); document.write( "2(8) = 5(3) + 1
\n" ); document.write( "16 = 15 + 1; confirms our solution
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\n" ); document.write( "Did this make sense to you? Any questions?\r
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