document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=135890>Question 135890</A>: <I><SPAN STYLE=\"word-break: break-all;\">  Find an equation of the line containing the given pair of points. <BR>\n" );
document.write( " (1/6, - 1/3)and (5/6,1)<BR>\n" );
document.write( "What is the equation of the line y? <BR>\n" );
document.write( "(y=mx+b) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #99547 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=99547\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> FIRST WE FIND THE SLOPE(m)<BR>\n" );
document.write( "SLOPE=(Y2-Y1)/(X2-X1)=(1+1/3)/(5/6-1/6)=(4/3)/(4/6)= (4/3)/(2/3)=4/3*3/2=12/6=2<BR>\n" );
document.write( "-1/3=2*1/6+b<BR>\n" );
document.write( "-1/3=1/3+b<BR>\n" );
document.write( "b=-1/3-1/3<BR>\n" );
document.write( "b=-2/3<BR>\n" );
document.write( "THUS THIS LINE EQUATION IS:<BR>\n" );
document.write( "Y=2X-2/3 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );