document.write( "Question 135879This question is from textbook
\n" ); document.write( ": 45. log (x+2)+ log (x-2)=1
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\n" ); document.write( "\n" ); document.write( "47. log (4x)+ log (x+3)=log x
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Algebra.Com's Answer #99546 by edjones(8007)\"\" \"About 
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log[5](x+2)+log[5](x-2)=1
\n" ); document.write( "log[5](x+2)(x-2)=1
\n" ); document.write( "5^log[5](x+2)(x-2)=5^1
\n" ); document.write( "(x+2)(x-2)=5
\n" ); document.write( "x^2-4=5
\n" ); document.write( "x^2-9=0
\n" ); document.write( "(x+3)(x-3)=0
\n" ); document.write( "x=3
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\n" ); document.write( "log[7](4x)+log[7](x+3)=log[7]x
\n" ); document.write( "log[7](4x)(x+3)=log[7]x
\n" ); document.write( "7^log[7](4x^2+12x)=7^log[7]x
\n" ); document.write( "4x^2+12x=x
\n" ); document.write( "4x^2+11x=0
\n" ); document.write( "x(4x+11)=0
\n" ); document.write( "4x=-11
\n" ); document.write( "x=-11/4 This is not in the domain of logrithms.
\n" ); document.write( "x=0 the answer is undefined.
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\n" ); document.write( "Ed \r
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