document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=135800>Question 135800</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi can you help me with this math problem?\r<BR>\n" );
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document.write( "8.) Solve the problem\r<BR>\n" );
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document.write( "An initial investment of $1000 is appreciated for 4 years in an account that earns 7% interest, compounded semiannually. Find the amount of money in the account at the end of the period. \r<BR>\n" );
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document.write( "the answer should be $1316.81 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #99501 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=99501\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P(1+R/N)^A*N P=PRINCIPLE, R=RATE, N=NUMBER OF INSTALLMENTS PER YEAR & A=NO. OF YEARS. <BR>\n" );
document.write( "1000(1+.07/2)^4*2<BR>\n" );
document.write( "1000(1.035)^8<BR>\n" );
document.write( "1000(1.31681)<BR>\n" );
document.write( "$1,316.81 ANSWER. </SPAN>\n" );
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