document.write( "Question 135744: I'm in an online class so there is no textbook, please help, thanks.\r
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document.write( "A sample of 25 concession stand purchases at the October 22 matinee of Bride of Chucky showed a mean purchase of $5.29 with a standard deviation of $3.02. For the October 26 evening showing of the same movie, for a sample of 25 purchases the mean was $5.12 with a standard deviation of $2.14. The means appear to be very close, but not the variances. At α = .05, is there a difference
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document.write( "in variances? Show all steps clearly, including an illustration of the decision rule. \n" );
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Algebra.Com's Answer #99487 by stanbon(75887) ![]() You can put this solution on YOUR website! A sample of 25 concession stand purchases at the October 22 matinee of Bride of Chucky showed a mean purchase of $5.29 with a standard deviation of $3.02. For the October 26 evening showing of the same movie, for a sample of 25 purchases the mean was $5.12 with a standard deviation of $2.14. The means appear to be very close, but not the variances. At α = .05, is there a difference \n" ); document.write( "in variances? \n" ); document.write( "------------------------------- \n" ); document.write( "Ho: s^2(matinee)-s^2(evening) = 0 \n" ); document.write( "Ho: difference is not 0 \n" ); document.write( "------------------------ \n" ); document.write( "Test statistic: F= s1^2/s2^2 = (2.14)^2/3.02^2 = 0.5021... \n" ); document.write( "-------------- \n" ); document.write( "Critical values for two-tail test with alpha-5%: \n" ); document.write( "left tail(F=0.44) \n" ); document.write( "right tail (F=2.27) \n" ); document.write( "------------------------------ \n" ); document.write( "Conclusion: Since test stat is not in either rejection interval, \n" ); document.write( "Fail to reject Ho; variances are statistically the same, based \n" ); document.write( "on this test. \n" ); document.write( "==================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |