document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=135700>Question 135700</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello, this is the problem: The sum of two numbers is 4 less than twice the larger. If the larger is decreased by three times the smaller, the result is -20.<BR>\n" );
document.write( "   Thank you<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #99442 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=99442\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The sum of two numbers is 4 less than twice the larger. If the larger is decreased by three times the smaller, the result is -20.<BR>\n" );
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document.write( "EQUATIONS:<BR>\n" );
document.write( "x+y = 2x+4<BR>\n" );
document.write( "x-3y = -20<BR>\n" );
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document.write( "x= 3y-20<BR>\n" );
document.write( "Substitute to get:<BR>\n" );
document.write( "3y-20+y = 2(3y-20)+4<BR>\n" );
document.write( "4x-20 = 6y-56<BR>\n" );
document.write( "2y = 36 (the smaller number)<BR>\n" );
document.write( "y = 18<BR>\n" );
document.write( "--------------<BR>\n" );
document.write( "x = 3*18-20<BR>\n" );
document.write( "x = 34 (the larger number)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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