document.write( "Question 20668: Can anyone help with this problem?\r
\n" ); document.write( "\n" ); document.write( "The tens digit of a two-digit number is 7 less than twice the units digit. If the digits are reversed, the new number is 13 more than twice the original number. Find the original number.\r
\n" ); document.write( "\n" ); document.write( "I started with\r
\n" ); document.write( "\n" ); document.write( "x = units
\n" ); document.write( "y = tens - [2x-7=y]\r
\n" ); document.write( "\n" ); document.write( "2(10y + x )+ 13 = 10x + y
\n" ); document.write( "but end up with
\n" ); document.write( "y = 8/19x - 13/19\r
\n" ); document.write( "\n" ); document.write( "2x-7 = 8/19x + 13/9
\n" ); document.write( "but ended up with
\n" ); document.write( "30/19x = 76/9\r
\n" ); document.write( "\n" ); document.write( "I know the answer is 14
\n" ); document.write( "but I am so lost!l Please help!\r
\n" ); document.write( "\n" ); document.write( "Thanks,
\n" ); document.write( "Sandy
\n" ); document.write( "

Algebra.Com's Answer #9944 by venugopalramana(3286)\"\" \"About 
You can put this solution on YOUR website!
Answer 9943 by venugopalramana(368) About Me on 2005-11-27 11:27:42 (Show Source):
\n" ); document.write( "SEE MY COMMENTS IN CAPITAL LETTERS
\n" ); document.write( "Can anyone help with this problem?
\n" ); document.write( "The tens digit of a two-digit number is 7 less than twice the units digit. If the digits are reversed, the new number is 13 more than twice the original number. Find the original number.
\n" ); document.write( "I started with
\n" ); document.write( "x = units............OK
\n" ); document.write( "y = tens .....SO THE NUMBER IS YX.....AND ...[2x-7=y]......GOOD..NOW YOU BETTER WRITE THE VALUE OF THIS NUMBER
\n" ); document.write( "VALUE OF NUMBER = 10Y+X=10(2X-7)+X=20X-70+X=21X-70
\n" ); document.write( "NOW THE DIGITS ARE REVERSED...SO THE NUMBER IS XY...THE VALUE OF THIS NUMBER IS
\n" ); document.write( "10X+Y =10X+2X-7=12X-7...NOW WE ARE GIVEN THAT
\n" ); document.write( "2*(21X-70)+13=12X-7.
\n" ); document.write( "42X-140+13=12X-7
\n" ); document.write( "42X-12X=140-13-7=120
\n" ); document.write( "30X=120
\n" ); document.write( "X=4
\n" ); document.write( "SO Y = 2X-7=2*4-7=1
\n" ); document.write( "SO THE ORIGINAL NUMBER IS YX = 14....WHICH YOU CAN EASILY VERIFY..NOW YOU DID EXTREMELY WELL I SHOULD SAY BUT MADE A SMALL AITHMATIC ERROR AS SHOWN BELOW
\n" ); document.write( "2(10y + x )+ 13 = 10x + y..............EXCELLENT
\n" ); document.write( "but end up with
\n" ); document.write( "y = 8/19x - 13/19...VERY GOOD
\n" ); document.write( "2x-7 = 8/19x + 13/9..............HOW YOU MADE A SIMPLE COPYING MISTAKE..IT IS
\n" ); document.write( "2X-7=(8/19)X-13/19..SO
\n" ); document.write( "(30/19)X=120/19
\n" ); document.write( "X=(120/19)*(19/30)=4..GOT IT ....I AM REALLY IMPRESSED BY YOUR WORKING IT IS VERY GOOD AND YOU GOT THE ANSWER ALMOST EXCEPT FOR THAT SIMPLE MITAKE...CONCENTRATE A BIT MORE AND YOU WILL SUCCEED..GOD LUCK
\n" ); document.write( "but ended up with
\n" ); document.write( "30/19x = 76/9.....
\n" ); document.write( "I know the answer is 14
\n" ); document.write( "but I am so lost!l Please help!
\n" ); document.write( "Thanks,
\n" ); document.write( "Sandy
\n" ); document.write( "0 solutions
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