document.write( "Question 135700: Hello, this is the problem: The sum of two numbers is 4 less than twice the larger. If the larger is decreased by three times the smaller, the result is -20.
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Algebra.Com's Answer #99439 by vleith(2983)\"\" \"About 
You can put this solution on YOUR website!
Let x be the smaller number and y be the larger one.\r
\n" ); document.write( "\n" ); document.write( "\"x+%2B+y+=+2y+-4\"
\n" ); document.write( "\"x+%2B+4+=+y\"\r
\n" ); document.write( "\n" ); document.write( "\"y+-+3x+=+-20\" sub for y using the value above\r
\n" ); document.write( "\n" ); document.write( "\"%28x%2B4%29+-+3x+=+-20\"
\n" ); document.write( "\"+-2x+%2B+4+=+-20\"
\n" ); document.write( "\"+-2x+=+-24+\"
\n" ); document.write( "\"x+=+12\"\r
\n" ); document.write( "\n" ); document.write( "Which means y = 16\r
\n" ); document.write( "\n" ); document.write( "Check your answer. Is (12+16) = (32-4)??? yes it is!
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