document.write( "Question 20664: I am getting really frustrated because I don't know how to go about solving this at all. Use log5 = 0.6990 and log
7 = 0.8451 to evaluate log
0.05 PLEASE walk me through this!! \n" );
document.write( "
Algebra.Com's Answer #9942 by venugopalramana(3286) You can put this solution on YOUR website! you mean log 5 to base 10=0.6990 etc..since all logs are to base 10 we may take it for granted and drop writing that base..so we have \n" ); document.write( "log 5 = 0.6990 \n" ); document.write( "log 7 =0.8451 \n" ); document.write( "to find log 0.05 \n" ); document.write( "log 0.05=log (5/100)=log 5 - log 100 = 0.6990 - 2 = -1.3010... \n" ); document.write( "since log 100 to base 10 =2...note that 10^2 = 100 .... \n" ); document.write( "hence by definition log 100 to base 10 =2.. \n" ); document.write( " |