document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=135602>Question 135602</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3(v-4)-2=6(v+3) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #99382 by </B><A HREF=/tutors/aboutme.mpl?userid=baholik06><B>baholik06(4)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=baholik06><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=99382\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First you need to distribute 3 to (v-4) and 6 to (v+3). So you will have 3v-12-2=6v+18. Combine like varibles. 3v-14=6v+18. Get v by itself. Subtract 3v from 6v to get -14=3v+18 and subtract 18 from -14 to get -32=3v. Then divide 3 to -32 to get v=-32/3. It doesn't break down any further so that is your answer. v=-32/3. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );