document.write( "Question 135619: A chemist is making 200 L of a solution that is 62% acid. He is mixing an 80% acid solution with a 30% acid solution. How much of the 80% acid solution will he use? \n" ); document.write( "
Algebra.Com's Answer #99361 by stanbon(75887)\"\" \"About 
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A chemist is making 200 L of a solution that is 62% acid. He is mixing an 80% acid solution with a 30% acid solution. How much of the 80% acid solution will he use?
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\n" ); document.write( "80% solution DATA:
\n" ); document.write( "Amt = x liters; amount of acid is 0.8x liters
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\n" ); document.write( "30% solution DATA:
\n" ); document.write( "Amt = 12-x liters; amt of acid is 0.3(12-x) = 3.6-0.3x liters
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\n" ); document.write( "Misture DATA:
\n" ); document.write( "Amt = 12 liters; amt of acid is 0.62*12 = 7.44 liters
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\n" ); document.write( "EQUATION:
\n" ); document.write( "acid + acid = acid
\n" ); document.write( "0.8x + 2.6-0.3x = 7.44
\n" ); document.write( "0.5x = 4.84
\n" ); document.write( "x = 9.68 liters of 80% solution in the mixture
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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