document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=135618>Question 135618</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am having trouble remembering how to start complex fractions. I know to multiply by the inverse, but it is ot making any sence to me. Here is the Expression <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%283%2B1%2F3b%29%2F%282-1%2F6b%29 ALIGN=MIDDLE  ALT=\"%283%2B1%2F3b%29%2F%282-1%2F6b%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >. Thank you for your time in helping me with this troublesome expression. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #99358 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=99358\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (3+(1/3b))/(2-(1/6b))\r<BR>\n" );
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document.write( "= [(9b+1)/3b] / [(12b-1)/6b]\r<BR>\n" );
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document.write( "Invert the denominator and multiply to get:\r<BR>\n" );
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document.write( "= [(9b+1)/3b] / [6b/(12b-1)]\r<BR>\n" );
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document.write( "= [2(9b+1)/(12b-1)]\r<BR>\n" );
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document.write( "= [24b-2]/[12b-1]<BR>\n" );
document.write( "=====================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
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