document.write( "Question 135562: The accounting department at Weston Materials, Inc., a national manufacturer of unattached
\n" ); document.write( "garages, reports that it takes two construction workers a mean of 32 hours and a
\n" ); document.write( "standard deviation of 2 hours to erect the Red Barn model. Assume the assembly times follow
\n" ); document.write( "the normal distribution.
\n" ); document.write( "a. Determine the z values for 29 and 34 hours. What percent of the garages take between
\n" ); document.write( "32 hours and 34 hours to erect?
\n" ); document.write( "b. What percent of the garages take between 29 hours and 34 hours to erect?
\n" ); document.write( "c. What percent of the garages take 28.7 hours or less to erect?
\n" ); document.write( "d. Of the garages, 5 percent take how many hours or more to erect?\r
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Algebra.Com's Answer #99342 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
it takes two construction workers a mean of 32 hours and a standard deviation of 2 hours to erect the Red Barn model. Assume the assembly times follow
\n" ); document.write( "the normal distribution.
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\n" ); document.write( "a. Determine the z values for 29 and 34 hours. What percent of the garages take between 32 hours and 34 hours to erect?
\n" ); document.write( " P(32 < x <34) = P(0 < z < 1)=0.3413
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\n" ); document.write( "b. What percent of the garages take between 29 hours and 34 hours to erect?
\n" ); document.write( "P(29 < x <34) = P (-1.5 < z < 0)=0.4332
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\n" ); document.write( "c. What percent of the garages take 28.7 hours or less to erect?
\n" ); document.write( "P(0 < x < 28.7) = P(-16 < x < -1.65) = 0.0495
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\n" ); document.write( "d. Of the garages, 5 percent take how many hours or more to erect?
\n" ); document.write( "Find the z-score associated with the upper 5%: z=1.645
\n" ); document.write( "Find the corresponding x-score using z=(x-u)/s
\n" ); document.write( "1.645 = (x-32)2
\n" ); document.write( "x-32 = 2*1.645
\n" ); document.write( "x = 3.290+32 = 35.29 hours
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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