document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=135564>Question 135564</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The number of passengers on the Carnival Sensation during one-week cruises in the<BR>\n" );
document.write( "Caribbean follows the normal distribution. The mean number of passengers per cruise is<BR>\n" );
document.write( "1,820 and the standard deviation is 120.<BR>\n" );
document.write( "a. What percent of the cruises will have between 1,820 and 1,970 passengers?<BR>\n" );
document.write( "b. What percent of the cruises will have 1,970 passengers or more?<BR>\n" );
document.write( "c. What percent of the cruises will have 1,600 or fewer passengers?<BR>\n" );
document.write( "d. How many passengers are on the cruises with the fewest 25 percent of passengers?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #99340 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=99340\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The number of passengers on the Carnival Sensation during one-week cruises in the<BR>\n" );
document.write( "Caribbean follows the normal distribution. The mean number of passengers per cruise is 1,820 and the standard deviation is 120.<BR>\n" );
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document.write( "You need to convert these numbers to z-scores then use your chart of calculator<BR>\n" );
document.write( "to find the percentages.<BR>\n" );
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document.write( "a. What percent of the cruises will have between 1,820 and 1,970 passengers?<BR>\n" );
document.write( "P(1820<x<1970)=P(0<z<1.25) = 0.3943<BR>\n" );
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document.write( "b. What percent of the cruises will have 1,970 passengers or more?<BR>\n" );
document.write( "P(x>=1970) = 0.5-0.3943 = 0.1056<BR>\n" );
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document.write( "c. What percent of the cruises will have 1,600 or fewer passengers?<BR>\n" );
document.write( "P(0<x<1600) = P (-15.1667<z<-1.8333 ) =0.0334<BR>\n" );
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document.write( "d. How many passengers are on the cruises with the fewest 25 percent of passengers?<BR>\n" );
document.write( "The z-value corresponding to lowest 25% is -0.6745<BR>\n" );
document.write( "Use z=(x-u)/s to find the corresponding x-score.<BR>\n" );
document.write( "-0.6745 = (x-1820)/120<BR>\n" );
document.write( "x-1820 = 120*-0.6745<BR>\n" );
document.write( "x-1820= -80.9388<BR>\n" );
document.write( "x = 1539 (rounded down)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. <BR>\n" );
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