document.write( "Question 135555This question is from textbook
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document.write( ": A 20 minute consumer survey mailed to 500 adults aged 25-34 included a $5 Starbucks gift certificate.The same survey was mailed to 500 adults aged 25-34 without the gift certificate. There were 65 responses from the first group and 45 from the second group.(a)Perform a two tailed test comparing the response rates(proportions)at ∝ = .05. (b) Form a confidence interval for the difference of proportions, without pooling the samples. Does it include zero?
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Algebra.Com's Answer #99321 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A 20 minute consumer survey mailed to 500 adults aged 25-34 included a $5 Starbucks gift certificate.The same survey was mailed to 500 adults aged 25-34 without the gift certificate. There were 65 responses from the first group and 45 from the second group. \n" ); document.write( "(a)Perform a two tailed test comparing the response rates(proportions)at ∝ = .05. \n" ); document.write( "----------------------------------------------------------------------- \n" ); document.write( "p-hat with certificate = 65/500 = 0.13 \n" ); document.write( "p-hat no certificate = 45/500 = 0.09 \n" ); document.write( "------------------------------------------- \n" ); document.write( "Ho: p-hats difference = 0 \n" ); document.write( "Ha: p-hats no difference \n" ); document.write( "Pooled: p-bar = (65+45)/1000 = 110/1000 = 0.11 \n" ); document.write( "---------------------------- \n" ); document.write( "Crit value: z = +/- 1.96 \n" ); document.write( "---------------------------- \n" ); document.write( "Test Stat: z(0.13-0.09) = (0.04-0)/sqrt[(0.11)(0.89)/500 + (0.11)(0.89)/500] \n" ); document.write( "= 0.04/0.019789 = 2.02 \n" ); document.write( "----------------------------- \n" ); document.write( "Conclusion: Test stat is greater than crit value so Reject Ho. \n" ); document.write( "====================================================================== \n" ); document.write( "(b) Form a confidence interval for the difference of proportions, without pooling the samples. p-hat(diff)=(0.13-0.09) \n" ); document.write( "E = 1.96sqrt[(0.13)(0.87)/500 + (0.09)(0.91)/500] = 1.96*0.019748=0.03871 \n" ); document.write( "CI: 0.04-0.03871 < p < 0.04+0.03871 \n" ); document.write( "------------------------------------ \n" ); document.write( "Does it include zero? No \n" ); document.write( "==================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |