document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=135550>Question 135550</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/9780321499134/algebrahomeworkh>college algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Use the factor theorem to decide whether the second polynomial is a factor of the first.\r<BR>\n" );
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document.write( "x^3 + 4x^2 + x - 6; x - 1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #99316 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=99316\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use the factor theorem to decide whether the second polynomial is a factor of the first.<BR>\n" );
document.write( "f(x) = x^3 + 4x^2 + x - 6; x - 1<BR>\n" );
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document.write( "x-1 will be a factor of f(x) is f(1)=0<BR>\n" );
document.write( "Using synthetic division you get:<BR>\n" );
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document.write( "1)....1....4....1....-6<BR>\n" );
document.write( ".......1....5....6..|..0\r<BR>\n" );
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document.write( "Remainder = 0, so f(1)=0, and x-1 is a factor of f(x)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
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