document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=135553>Question 135553</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/1567655157/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Theres a parallelogram slanted to the right. (SRQP) M is in between SR and connects to the bottom right angle, angle Q, making MQ. T is in between PQ and connects up to the top left angle, angle S. So the top of the shape is SMR, and the bottom is PTQ. Given: PQRS is a parallelagram and PT is congruent to RM. Prove TQMS is a parallelagram. by the way, the book is called course 2, integrated mathematics, 3rd edition. chapter 7, page 268, this one os problem 11 but if anyone knows problems 11-13 and 15 you would be awesomeeee=]<BR>\n" );
document.write( "thankss.<BR>\n" );
document.write( "PLEASE HELPPPP!!! </SPAN>\n" );
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