document.write( "Question 135538: the area of a rectangular field is 1200 m^2. two parallel sides are fenced with aluminum at $20/m. the remaining two sides are fenced with steel at $10/m. the total cost is $2200\r
\n" ); document.write( "\n" ); document.write( "a. what is the length of each side fenced with aluminum?
\n" ); document.write( "b. what is the length of each side fenced with steel?
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Algebra.Com's Answer #99312 by josmiceli(19441)\"\" \"About 
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Call the length of a side fenced with aluminum \"a\"
\n" ); document.write( "Call the length of a side fenced with steel \"s\"
\n" ); document.write( "\"a%2As+=+1200\" m2
\n" ); document.write( "The total length of aluminum fence = \"2a\"
\n" ); document.write( "The total length of steel fence = \"2s\"
\n" ); document.write( "\"20%2A%282a%29+%2B+10%2A%282s%29+=+2200\"
\n" ); document.write( "\"40a+%2B+20s+=+2200\"
\n" ); document.write( "\"s+=+1200%2Fa\"
\n" ); document.write( "\"40a+%2B+20%2A%281200%2Fa%29+=+2200\"
\n" ); document.write( "\"40a%5E2+%2B+24000+=+2200a\"
\n" ); document.write( "\"a%5E2+-+55a+%2B+600+=+0\"
\n" ); document.write( "Use the quadratic formuala
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "\"a+=+1\"
\n" ); document.write( "\"b+=+-55\"
\n" ); document.write( "\"c+=+600\"
\n" ); document.write( "\"x+=+%28-%28-55%29+%2B-+sqrt%28+%28-55%29%5E2-4%2A1%2A600+%29%29%2F%282%2A1%29+\"
\n" ); document.write( "\"x+=+%2855+%2B-+sqrt%28+3025+-+2400+%29%29%2F2+\"
\n" ); document.write( "\"x+=+%2855+%2B-+sqrt%28+625+%29%29%2F2+\"
\n" ); document.write( "\"x+=+%2855+%2B-+25%29%2F2+\"
\n" ); document.write( "\"x+=+40\"
\n" ); document.write( "\"x+=+15\"
\n" ); document.write( "If \"a+=+40\", then \"s+=+1200%2Fa\" and
\n" ); document.write( "\"s+=+30\"
\n" ); document.write( "\"40a+%2B+20s+=+2200\"
\n" ); document.write( "\"40%2A40+%2B+20%2A30+=+2200\"
\n" ); document.write( "\"1600+%2B+600+=+2200\"
\n" ); document.write( "----------------------
\n" ); document.write( "If \"a+=+15\", then
\n" ); document.write( "\"s+=+80\"
\n" ); document.write( "\"40a+%2B+20s+=+2200\"
\n" ); document.write( "\"40%2A15+%2B+20%2A80+=+2200\"
\n" ); document.write( "\"600+%2B+1600+=+2200\"
\n" ); document.write( "----------------------
\n" ); document.write( "The length of each side fenced with aluminum can be 40 m and the
\n" ); document.write( "length of a side fenced with steel will be 30 m
\n" ); document.write( "-----------------------
\n" ); document.write( "The length of the side fenced with aluminum can also be 15 m and
\n" ); document.write( "the length of a side fenced with steel will be 80 m
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