document.write( "Question 135537This question is from textbook
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document.write( ": A student walks and jogs to college each day. The student averages 5km/h walking and 9km/h jogging. The distance from home to college is 8km, and the student makes the trip in 1 hour. How far does the student jog? \n" );
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Algebra.Com's Answer #99311 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! A student walks and jogs to college each day. The student averages 5km/h walking and 9km/h jogging. The distance from home to college is 8km, and the student makes the trip in 1 hour. How far does the student jog? \n" ); document.write( ": \n" ); document.write( "Let x = distance jogged \n" ); document.write( "then \n" ); document.write( "(8-x) = distance walked: \n" ); document.write( ": \n" ); document.write( "Write a time equation: Time = dist/speed \n" ); document.write( ": \n" ); document.write( "Walk time + jog time = 1 hr \n" ); document.write( " \n" ); document.write( "; \n" ); document.write( "Multiply equation by 45 to get rid of the denominators \n" ); document.write( "45* \n" ); document.write( "9(8-x) + 5x = 45 \n" ); document.write( ": \n" ); document.write( "72 - 9x + 5x = 45 \n" ); document.write( ": \n" ); document.write( "-4x = 45 - 72 \n" ); document.write( ": \n" ); document.write( "-4x = -27 \n" ); document.write( "; \n" ); document.write( "x = -27/-4 \n" ); document.write( ": \n" ); document.write( "x = 6.75 km jogged \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "Check solution: 8 - 6.75 = 1.25 km walked; check using the time equation \n" ); document.write( "1.25/5 + 6.75/9 = \n" ); document.write( ".25 + .75 = 1 \n" ); document.write( " |