document.write( "Question 20543: What is the value of X in this logarithm? log\"6\"(2x-5) + 1 = log\"6\"(7x+10) Please walk me through this equation. \n" ); document.write( "
Algebra.Com's Answer #9929 by Earlsdon(6294)\"\" \"About 
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Recall:\r
\n" ); document.write( "\n" ); document.write( "If log\"6\"a = log\"6\"b, then a = b\r
\n" ); document.write( "\n" ); document.write( "log\"6\"(2x-5) = log\"6\"(7x+10)
\n" ); document.write( "(2x-5) = (7x+10) Subtract 2x from both sides.
\n" ); document.write( "-5 = 5x+10 Subtract 10 to bothsides.
\n" ); document.write( "-15 = 5x Divide both sides by 5.
\n" ); document.write( "x = -3\r
\n" ); document.write( "\n" ); document.write( "Check:
\n" ); document.write( "log\"6\"(2(-3)-5) = log\"6\"(7(-3)+10)
\n" ); document.write( "log\"6\"(-11) = log\"6\"(-21+10)
\n" ); document.write( "log\"6\"(-11) = log\"6\"(-11)
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