document.write( "Question 135455This question is from textbook
\n" ); document.write( ": What quantity of a 60% acid solution must be mixed with a 30% solution to produce 300mL of a 50% solution? \n" ); document.write( "

Algebra.Com's Answer #99262 by checkley77(12844) $\"\"$ $\"About$

You can put this solution on YOUR website!
.6x+.3(300-x)=.5*300
\n" ); document.write( ".6x+90-.3x=150
\n" ); document.write( ".3x=150-90
\n" ); document.write( ".3x=60
\n" ); document.write( "x=60/.3
\n" ); document.write( "x=200 ml of 60% is used.
\n" ); document.write( "300-200=100 ml of 30% is used.
\n" ); document.write( "proof:
\n" ); document.write( ".6*200+.3*100=150
\n" ); document.write( "120+30=150
\n" ); document.write( "150=150 \n" ); document.write( "

\n" );