document.write( "Question 20616: Here is my question:\r
\n" ); document.write( "\n" ); document.write( "7^logx = 7\r
\n" ); document.write( "\n" ); document.write( "the answer is 10, but I am not quite sure what to do when the log is an exponent of 7. I'm also supposed to show a check of my answer.\r
\n" ); document.write( "\n" ); document.write( "Thanks
\n" ); document.write( "Sandy
\n" ); document.write( "

Algebra.Com's Answer #9926 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Recall this about logarithms:
\n" ); document.write( "If \"a%5Ex+=+a%5Ey\", the bases are the same, that is a = a, then the exponents are equal, therefore x = y. Applying this to your problem:\r
\n" ); document.write( "\n" ); document.write( "\"7%5E%28logx%29+=+7%5E1\" The bases are the same so the exponents are equal.\r
\n" ); document.write( "\n" ); document.write( "\"log%28x%29+=+1\" Change to exponential form.
\n" ); document.write( " Recall that log(x) is log to the base 10 of x:
\n" ); document.write( "Logarithmic form: y = log(x)...Exponential form: x = 10^y\r
\n" ); document.write( "\n" ); document.write( "\"x+=+10%5E1\"\r
\n" ); document.write( "\n" ); document.write( "So, x = 10\r
\n" ); document.write( "\n" ); document.write( "Check:
\n" ); document.write( "\"7%5E%28logx%29+=+7\"
\n" ); document.write( "\"7%5Elog10+=+7\" but log10 = 1
\n" ); document.write( "\"7%5E1+=+7\" \r
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