document.write( "Question 135410: Linda has $1.85 in quarters, nickels, and dimes. If she has three times as many dimes as quarters, and five fewer nickels than dimes, how many of each coin does she have? \n" ); document.write( "
Algebra.Com's Answer #99252 by ankor@dixie-net.com(22740)\"\" \"About 
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Write an equation for each statement
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\n" ); document.write( "Linda has $1.85 in quarters, nickels, and dimes.
\n" ); document.write( ".05n + .10d + .25q = 1.85
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\n" ); document.write( "If she has three times as many dimes as quarters,
\n" ); document.write( "q = d/3
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\n" ); document.write( "five fewer nickels than dimes,
\n" ); document.write( "n = (d - 5)
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\n" ); document.write( "how many of each coin does she have?
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\n" ); document.write( "Substitute (d/3) for q and (d-5) for n in the 1st equation:
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\n" ); document.write( ".05(d-5) + .10d + .25(d/3) = 1.85
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\n" ); document.write( ".05d - .25 + .10d +(.25d/3) = 1.85; multiplied what's inside the brackets
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\n" ); document.write( ".05d + .10d + (.25d/3) = 1.85 + .25; add .25 to both sides
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\n" ); document.write( ".15d + (.25d/3) = 2.10
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\n" ); document.write( ".45d + .25d = 6.30; multiplied equation by 3
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\n" ); document.write( ".70d = 6.30
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\n" ); document.write( "d = 6.3/.7; divided both sides by .7
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\n" ); document.write( "d = 9 dimes
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\n" ); document.write( "nickels: 9 - 5 = 4 nickels (five fewer nickels than dimes,)
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\n" ); document.write( "Quarters: 9/3 = 3 quarters (three times as many dimes as quarters,)
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\n" ); document.write( "Check solutions:
\n" ); document.write( ".05(4) + .10(9) + .25(3) =
\n" ); document.write( ".20 + .90 + .75 = 1.85
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