document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=135430>Question 135430</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi. I'm am required to find x in this equation: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=log+%285%2C+%285-4x%29%29 ALIGN=MIDDLE  ALT=\"log+%285%2C+%285-4x%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=log+%28sqrt%285%29%2C+%282-x%29%29 ALIGN=MIDDLE  ALT=\"log+%28sqrt%285%29%2C+%282-x%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >. My teacher told me answer is +1 or -1. I do know the formula - Change of Base Law - to solve the equation, but the problem is, I do not know how to apply the formula due to the square root of 5 as the base of the equation.\r<BR>\n" );
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document.write( "I've tried by using the formula to change <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=log+%285%2C+%285-4x%29%29 ALIGN=MIDDLE  ALT=\"log+%285%2C+%285-4x%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=log+%28sqrt%285%29%2C+%285-4x%29%29 ALIGN=MIDDLE  ALT=\"log+%28sqrt%285%29%2C+%285-4x%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >/<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=log+%28sqrt%285%29%2C+sqrt%285%29%29 ALIGN=MIDDLE  ALT=\"log+%28sqrt%285%29%2C+sqrt%285%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=log+%28sqrt%285%29%2C+%282-x%29%29 ALIGN=MIDDLE  ALT=\"log+%28sqrt%285%29%2C+%282-x%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=log+%28sqrt%285%29%2C+%285-4x%29%29 ALIGN=MIDDLE  ALT=\"log+%28sqrt%285%29%2C+%285-4x%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >/1 = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=log+%28sqrt%285%29%2C+%282-x%29%29 ALIGN=MIDDLE  ALT=\"log+%28sqrt%285%29%2C+%282-x%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "5-4x = 2-x<BR>\n" );
document.write( "-3x = -3<BR>\n" );
document.write( "x = 1\r<BR>\n" );
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document.write( "However, I don't know how to find -1. Please teach me the correct method. Thanks.\r<BR>\n" );
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document.write( "(By the way, the answer is +1 with the + sign begin underlined. I hope you understand what I mean. And is this answer the same as 1 and -1? Thanks.) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #99251 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=99251\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve for x:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=log%285%2C%285-4x%29%29+=+log%28sqrt%285%29%2C%282-x%29%29 ALIGN=MIDDLE  ALT=\"log%285%2C%285-4x%29%29+=+log%28sqrt%285%29%2C%282-x%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Change the base of the second logarithm to that of the first using:<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=log%28b%2C%28M%29%29+=+%28log%28a%2C%28M%29%29%29%2F%28log%28a%2C%28b%29%29%29 ALIGN=MIDDLE  ALT=\"log%28b%2C%28M%29%29+=+%28log%28a%2C%28M%29%29%29%2F%28log%28a%2C%28b%29%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=log%28sqrt%285%29%2C%282-x%29%29+=+%28log%285%2C%282-x%29%29%29%2F%28log%285%2C%28sqrt%285%29%29%29%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" >=<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28log%285%2C%282-x%29%29%29%2F%281%2F2%29log%285%2C%285%29%29 ALIGN=MIDDLE  ALT=\"%28log%285%2C%282-x%29%29%29%2F%281%2F2%29log%285%2C%285%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >=<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2Alog%285%2C%282-x%29%29 ALIGN=MIDDLE  ALT=\"2%2Alog%285%2C%282-x%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "So, we end up with:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=log%285%2C%285-4x%29%29+=+2%2Alog%285%2C%282-x%29%29 ALIGN=MIDDLE  ALT=\"log%285%2C%285-4x%29%29+=+2%2Alog%285%2C%282-x%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > Applying the power rule to the right side:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=log%285%2C%285-4x%29%29+=+log%285%2C%282-x%29%5E2%29 ALIGN=MIDDLE  ALT=\"log%285%2C%285-4x%29%29+=+log%285%2C%282-x%29%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > therefore:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5-4x+=+%282-x%29%5E2 ALIGN=MIDDLE  ALT=\"5-4x+=+%282-x%29%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Simplifying:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5-4x+=+4-4x%2Bx%5E2 ALIGN=MIDDLE  ALT=\"5-4x+=+4-4x%2Bx%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Add 4x to both sides.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5+=+4%2Bx%5E2 ALIGN=MIDDLE  ALT=\"5+=+4%2Bx%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Subtract 5 from both sides.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=0+=+x%5E2-1 ALIGN=MIDDLE  ALT=\"0+=+x%5E2-1\"   DISABLED_style= \"max-width:90%; height:auto;\" > Factor the right side.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x%2B1%29%28x-1%29+=+0 ALIGN=MIDDLE  ALT=\"%28x%2B1%29%28x-1%29+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" > so...<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+1 ALIGN=MIDDLE  ALT=\"x+=+1\"   DISABLED_style= \"max-width:90%; height:auto;\" > or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+-1 ALIGN=MIDDLE  ALT=\"x+=+-1\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "The answer can be read as: x = + or - 1 </SPAN>\n" );
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