document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=135384>Question 135384</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I was wondering if you would be able to assist me with this problem...\r<BR>\n" );
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document.write( "y=x^2-2x-9\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #99235 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=99235\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x^2-2x-9=0<BR>\n" );
document.write( "x^2-2x  =9<BR>\n" );
document.write( "x^2-2x+1=9+1 comleting the square by dividing the middle term by 2 and squaring it and  last term.<BR>\n" );
document.write( "(x-1)^2=10<BR>\n" );
document.write( "x-1=+-sqrt(10) sqrt of each side.<BR>\n" );
document.write( "x=1+-sqrt(10)<BR>\n" );
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document.write( "Ed </SPAN>\n" );
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