document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=135408>Question 135408</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find two consecutive integers such that 3 times the first integer plus 2 times the second integer is equal to 107. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #99230 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=99230\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> LET X= THE FIRST INTEGER<BR>\n" );
document.write( "LET X+1=THE NEXT NUMBER<BR>\n" );
document.write( "3X+2(X+1)=107<BR>\n" );
document.write( "3X+2X+2=107<BR>\n" );
document.write( "5X=107-2<BR>\n" );
document.write( "X=105<BR>\n" );
document.write( "X=105/5<BR>\n" );
document.write( "X=21 IS THE FIRST INTEGER.<BR>\n" );
document.write( "21+1=22 IS THE NEXT NUMBER. <BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "3*21+2*22=107<BR>\n" );
document.write( "63+44=107<BR>\n" );
document.write( "107=107<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );