document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=114748>Question 114748</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of 6 times John's age and 5 times Mary's age is 150. John is 2 years less than twice as old as Mary. Find each of their ages. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #99218 by </B><A HREF=/tutors/aboutme.mpl?userid=awang1996><B>awang1996(50)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=awang1996><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=99218\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The sum of 6 times John's age and 5 times Mary's age is 150. John is 2 years less than twice as old as Mary. Find each of their ages.<BR>\n" );
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document.write( "6j+5m=150<BR>\n" );
document.write( "j=2m-2<br><BR>\n" );
document.write( "6(2m-2)+5m=150<BR>\n" );
document.write( "12m-12+5m=150<BR>\n" );
document.write( "17m-12=150<BR>\n" );
document.write( "17m=162<BR>\n" );
document.write( "m=approximetally 10<BR>\n" );
document.write( "j=approximetally 18 </SPAN>\n" );
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