document.write( "Question 135422: Tutor: How do Isubtract and simplify 5 square root of 20 minus 2 square root of 125? \n" ); document.write( "
Algebra.Com's Answer #99215 by nycsharkman(136)![]() ![]() ![]() You can put this solution on YOUR website! How do I subtract and simplify 5 square root of 20 minus 2 square root of 125?\r \n" ); document.write( "\n" ); document.write( "5(sqrt{20}) - 2(sqrt{125})\r \n" ); document.write( "\n" ); document.write( "You need to simplify the square roots individually.\r \n" ); document.write( "\n" ); document.write( "For each square root, look for two numbers that, when multiplied, will yield the number inside the radicand. However, one of the factors has to be a perfect square.\r \n" ); document.write( "\n" ); document.write( "sqrt{20} = sqrt{4} times sqrt{5}\r \n" ); document.write( "\n" ); document.write( "The square root of 4 is a perfect square because 2 times 2 = 4.\r \n" ); document.write( "\n" ); document.write( "Then, the square root of 4 = 2.\r \n" ); document.write( "\n" ); document.write( "The square root of 5 is NOT a perfect square and it is also in lowest term. \n" ); document.write( "So, leave it alone.\r \n" ); document.write( "\n" ); document.write( "==============================\r \n" ); document.write( "\n" ); document.write( "sqrt{125} = sqrt{25} times sqrt{5}\r \n" ); document.write( "\n" ); document.write( "The square root of 25 is 5 because 5 times 5 = 25.\r \n" ); document.write( "\n" ); document.write( "Then, the square root of 25 is 5.\r \n" ); document.write( "\n" ); document.write( "Again, the square root of 5 is NOT a perfect square and it is also in lowest term. Leave it alone.\r \n" ); document.write( "\n" ); document.write( "We now have this:\r \n" ); document.write( "\n" ); document.write( "5(2)(sqrt{5}) - 2(5)(sqrt{5})\r \n" ); document.write( "\n" ); document.write( "10(sqrt{5}) - 10(sqrt(5}) = 0\r \n" ); document.write( "\n" ); document.write( "The answer is 0.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |