document.write( "Question 135398: Find one of the solution of x= square root 3x-12 + 4 \n" ); document.write( "
Algebra.Com's Answer #99203 by ankor@dixie-net.com(22740)\"\" \"About 
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Find one of the solution of x= square root 3x-12 + 4
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\n" ); document.write( "x = \"sqrt%283x-12%29\" + 4
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\n" ); document.write( "Subtract 4 from both sides:
\n" ); document.write( "x - 4 = \"sqrt%283x-12%29\"
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\n" ); document.write( "Square both sides:
\n" ); document.write( "(x-4)^2 = 3x - 12
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\n" ); document.write( "FOIL the left side:
\n" ); document.write( "x^2 -8x + 16 = 3x - 12
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\n" ); document.write( "Combine as a quadratic equation on the left
\n" ); document.write( "x^2 - 8x - 3x + 16 + 12 = 0
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\n" ); document.write( "x^2 - 11x + 28 = 0
\n" ); document.write( "Factor:
\n" ); document.write( "(x-4)(x-7) = 0
\n" ); document.write( "Solutions
\n" ); document.write( "x = 4
\n" ); document.write( "x = 7
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\n" ); document.write( "You can choose which solution you want. \n" ); document.write( "
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