document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=20603>Question 20603</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me with this problem:\r<BR>\n" );
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document.write( "logb^2 = .25596, logb^3 = .40568, logb^5 = .59432\r<BR>\n" );
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document.write( "logb^(5/12)^3\r<BR>\n" );
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document.write( "I know the answer is .096984, but don't know how to go about it.\r<BR>\n" );
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document.write( "Thanks,<BR>\n" );
document.write( "Sandy </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #9920 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=9920\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> logb^2 = .25596, logb^3 = .40568, logb^5 = .59432<BR>\n" );
document.write( "this is not properly written..i think by the above you meant log 2 to base b =0.25596..etc....then the  above has some meaning..otherwise they are not correct and represent contradictory things <BR>\n" );
document.write( "logb^(5/12)^3=?...as given above this should mean that we want log (5/12)^3 to base b.<BR>\n" );
document.write( "use the following formulae in logs which are true for any base..here wew can take b as base<BR>\n" );
document.write( "log x*y=log x+log y<BR>\n" );
document.write( "log x/y=log x-log y<BR>\n" );
document.write( "log x^n=n*log x<BR>\n" );
document.write( "log x to base b=log x /log b <BR>\n" );
document.write( "LET US TAKE ALL LOGS TO BASE b AS WE HAVE THEM TO BASE b IN THE PROBLEM.<BR>\n" );
document.write( "log(5/12)^3=3*log(5/12)<BR>\n" );
document.write( "=3*(log 5-log 12)=3*(log 5-log 2*2*3)<BR>\n" );
document.write( "=3*(log 5-log 2-log 2-log 3)=3*(0.59432-0.25596-0.25596-0.40568)<BR>\n" );
document.write( "3*(-0.3238)=-0.96984<BR>\n" );
document.write( "YOU GAVE THE ANSWER AS 0.096984...IN WHICH CASE THE QUESTION SHOULD BE log(5/12)^(-0.3)   to base b =????.PLEASE CHECK BACK THE QUESTION WRITE IT DOWN PROPERLY AS AS GIVEN IN THE TEXT AND COME BACK<BR>\n" );
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