document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=2361>Question 2361</A>: <I><SPAN STYLE=\"word-break: break-all;\"> log7^4x + log7^(x+1) = ½log7^64 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #992 by </B><A HREF=/tutors/aboutme.mpl?userid=longjonsilver><B>longjonsilver(2297)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=longjonsilver><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=longjonsilver><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=992\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> are you sure you mean ^ ie 7 to the power 4x or rather \"log of 4x, to the base 7\"?\r<BR>\n" );
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document.write( "Jon </SPAN>\n" );
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