document.write( "Question 135397: Here is another one I need help with. Thanks in Advance.\r
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document.write( "1. If I am surveying the constituents for my favorite candidate ... and I wish to be 95% confident of the estimate I develop for the proportion of the constituents that favor my candidate and i want the error to be within 2% (0.02) of the actual population proportion
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document.write( ">> how many folks do there need to be in my sample ??\r
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Algebra.Com's Answer #99195 by stanbon(75887) ![]() You can put this solution on YOUR website! If I am surveying the constituents for my favorite candidate ... and I wish to be 95% confident of the estimate I develop for the proportion of the constituents that favor my candidate and i want the error to be within 2% (0.02) of the actual population proportion\r \n" ); document.write( "\n" ); document.write( ">> how many folks do there need to be in my sample ?? \n" ); document.write( "------------------------------ \n" ); document.write( "Formula: E = z*sqrt(pq/n) \n" ); document.write( "sqrt(n) = z*(sqrt(pq)}/E \n" ); document.write( "n = [z/E}^2*pq \n" ); document.write( "------------------ \n" ); document.write( "z-score for 95^ confidence = 1.96 \n" ); document.write( "Since p is not given, avoid bias by letting p=1/2=q \n" ); document.write( "E is given as 0.02 \n" ); document.write( "------------------- \n" ); document.write( "n = [1.96/0.02]^2(1/4) \n" ); document.write( "n = 9604*(1/4) \n" ); document.write( "n = 2401 (desired sample size) \n" ); document.write( "=============================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |