document.write( "Question 135397: Here is another one I need help with. Thanks in Advance.\r
\n" ); document.write( "\n" ); document.write( "1. If I am surveying the constituents for my favorite candidate ... and I wish to be 95% confident of the estimate I develop for the proportion of the constituents that favor my candidate and i want the error to be within 2% (0.02) of the actual population proportion
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\n" ); document.write( ">> how many folks do there need to be in my sample ??\r
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Algebra.Com's Answer #99195 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
If I am surveying the constituents for my favorite candidate ... and I wish to be 95% confident of the estimate I develop for the proportion of the constituents that favor my candidate and i want the error to be within 2% (0.02) of the actual population proportion\r
\n" ); document.write( "\n" ); document.write( ">> how many folks do there need to be in my sample ??
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\n" ); document.write( "Formula: E = z*sqrt(pq/n)
\n" ); document.write( "sqrt(n) = z*(sqrt(pq)}/E
\n" ); document.write( "n = [z/E}^2*pq
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\n" ); document.write( "z-score for 95^ confidence = 1.96
\n" ); document.write( "Since p is not given, avoid bias by letting p=1/2=q
\n" ); document.write( "E is given as 0.02
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\n" ); document.write( "n = [1.96/0.02]^2(1/4)
\n" ); document.write( "n = 9604*(1/4)
\n" ); document.write( "n = 2401 (desired sample size)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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