document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=135391>Question 135391</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangular field is 140 yards. The land sells for $10/yd^2 and the total cost o the land is $12,000. What are the dimensions of the field? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #99194 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=99194\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangular field is 140 yards. The land sells for $10/yd^2 and the total cost of the land is $12,000. What are the dimensions of the field?<BR>\n" );
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document.write( "$12000/$10 = 1200 yd^2<BR>\n" );
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document.write( "EQUATIONS:<BR>\n" );
document.write( "L*W = 1200<BR>\n" );
document.write( "L+W = 70<BR>\n" );
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document.write( "L = 1200/W<BR>\n" );
document.write( "(1200/W) + W = 70<BR>\n" );
document.write( "1200 + W^2 = 70W<BR>\n" );
document.write( "W^2-70W+1200 = 0<BR>\n" );
document.write( "W = [70 +- sqrt(70^2-4*1200)]/2<BR>\n" );
document.write( "W = [70 +- srt(100)]/2<BR>\n" );
document.write( "W = [70 +- 10]/2<BR>\n" );
document.write( "W = 40 then L=30<BR>\n" );
document.write( "OR<BR>\n" );
document.write( "W = 30 then L = 40 <BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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