document.write( "Question 20604: Can anyone help with this one?\r
\n" ); document.write( "\n" ); document.write( "3^(2x+5) = 4\r
\n" ); document.write( "\n" ); document.write( "I started with (2x+5) log3 = log4
\n" ); document.write( "then 2xlog3 + 5log3 = log4\r
\n" ); document.write( "\n" ); document.write( "but now I'm lost,\r
\n" ); document.write( "\n" ); document.write( "I know the answer is -1.87
\n" ); document.write( "

Algebra.Com's Answer #9919 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
You got a good start.
\n" ); document.write( "\"3%5E%282x%2B5%29+=+4\" Take the log of both sides.
\n" ); document.write( "\"%282x%2B5%29log%283%29+=+log%284%29\" Divide both sides of the equation by log(3).
\n" ); document.write( "\"2x%2B5+=+%28log%284%29%29%2Flog%283%29\" Subtract 5 from both sides.
\n" ); document.write( "\"2x+=+%28%28log%284%29%29%2Flog%283%29%29+-+5\" Use you calculator to find \"%28log%284%29%29%2Flog%283%29\"
\n" ); document.write( "\"2x+=+1.262+-+5\"
\n" ); document.write( "\"2x+=+-3.738\" Divide both sides by 2.
\n" ); document.write( "\"x+=+-1.869\"
\n" ); document.write( "
\n" );