document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=135344>Question 135344</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Katy leaves City A for City B at 8 A.M., driving at 52 mi/h. At 10 A.M., Jensen leaves City B for City A, driving at 61 mi/h along the same route. If the cities are 443 mi apart, at what time (P.M.) will they meet?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #99173 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=99173\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 52X+61(X-2)=443<BR>\n" );
document.write( "52X+61X-122=443<BR>\n" );
document.write( "113X=443+122<BR>\n" );
document.write( "113X=565<BR>\n" );
document.write( "X=565/113<BR>\n" );
document.write( "X=5 HOURS AFTER KATY LEAVES THEY WILL MEET.<BR>\n" );
document.write( "8+5=13 OR 1 PM.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "52*5+61*3=443<BR>\n" );
document.write( "260+183=443<BR>\n" );
document.write( "443=443 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );