document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=135354>Question 135354</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One of two supplementary angles is 4 degree more than one-third of the other angle. find the measure of each angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #99167 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=99167\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> SUPPLEMENTARY ANGLES (2) ADD UP YO 180 DEGREES.<BR>\n" );
document.write( "THEREFORE:<BR>\n" );
document.write( "X=Y/3+4 & X+Y=180<BR>\n" );
document.write( "THUS WE HAVE THE EQUATION<BR>\n" );
document.write( "(Y/3+4)+Y=180<BR>\n" );
document.write( "Y/3+4+Y=180<BR>\n" );
document.write( "Y/3+Y=180-4<BR>\n" );
document.write( "(Y+3Y)/3=176<BR>\n" );
document.write( "4Y=176*3<BR>\n" );
document.write( "4Y=528<BR>\n" );
document.write( "Y=528/4<BR>\n" );
document.write( "Y=132 DEGREES IS THE LARGER ANGLE.<BR>\n" );
document.write( "X=132=180<BR>\n" );
document.write( "X=180-132<BR>\n" );
document.write( "X=48 DEGREES FOR THE SMALLER ANGLE.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "132/3+4+132=180<BR>\n" );
document.write( "44+4+132=180<BR>\n" );
document.write( "180=180<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );