document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=135355>Question 135355</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the complement of an angle is 5 degree less than one-sixth of its supplement, find the measure of the angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #99165 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=99165\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the complement of an angle is 5 degree less than one-sixth of its supplement, find the measure of the angle.<BR>\n" );
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document.write( "Let the angle be \"x\"; then the complement is \"90-x\"; the supplement is \"180-x\"<BR>\n" );
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document.write( "EQUATION:<BR>\n" );
document.write( "90-x = (1/6)(180-x)-5<BR>\n" );
document.write( "90-x = 30-(x/6) -5<BR>\n" );
document.write( "65-x =-(x/6)<BR>\n" );
document.write( "(5/6)x = 65<BR>\n" );
document.write( "x = 65(6/5)= 78 degrees<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.  </SPAN>\n" );
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