document.write( "Question 135339This question is from textbook College Algebra
\n" ); document.write( ": Thank you for taking the time to help. Here is the target graph equation and the first of a four part question;\r
\n" ); document.write( "\n" ); document.write( "Use the graph of y = x^2 -2x -8 to answer the following: a) Using the graph, what are the solution(s) to the equation x^2 - 2x -8 =0?\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
Algebra.Com's Answer #99159 by Nate(3500)\"\" \"About 
You can put this solution on YOUR website!
First, you should always try to factor. Factoring can reduce a lot of work. If the function can not be factored, you would then use the quadratic formula (a quicker way is 'solving the square' if you know how).
\n" ); document.write( "ax^2 + bx + c = 0 .. you look for factors of ac that sum to b
\n" ); document.write( "1x^2 - 2x - 8 = 0 .. you look for factors of -8 that sum to -2
\n" ); document.write( "-8 : -1,8
\n" ); document.write( "-8 : -2,4
\n" ); document.write( "-8 : -4,2 ... here we are
\n" ); document.write( "-8 : -8,1
\n" ); document.write( "x^2 - 4x + 2x - 8 = 0 .. mearly break the linear variable's coefficient
\n" ); document.write( "(x^2 - 4x) + (2x - 8) = 0 .. group
\n" ); document.write( "x(x - 4) + 2(x - 4) = 0 .. factor out
\n" ); document.write( "(x + 2)(x - 4) = 0
\n" ); document.write( "x + 2 = 0 and x - 4 = 0 .. zero property
\n" ); document.write( "x = -2 and x = 4 \n" ); document.write( "
\n" );