document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=135336>Question 135336</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find three consecutive odd integers such that the sum of the first and twice the second is 6 more than the third </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #99158 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=99158\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = the first odd number, then x+2 is the next consecutive odd number and x+4 is the next one.<BR>\n" );
document.write( "From the problem description, you can write:<BR>\n" );
document.write( "x+2(x+2) = (x+4)+6 Simplify and solve for x.<BR>\n" );
document.write( "x+2x+4 = x+10<BR>\n" );
document.write( "3x+4 = x+10 Subtract x from both sides.<BR>\n" );
document.write( "2x+4 = 10 Subtract 4 from both sides.<BR>\n" );
document.write( "2x = 6 Divide both sides by 2.<BR>\n" );
document.write( "x = 3 and...<BR>\n" );
document.write( "x+2 = 5 and...<BR>\n" );
document.write( "x+4 = 7 </SPAN>\n" );
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