document.write( "Question 135276: Could anyone please help me with this problem? Thank You!\r
\n" ); document.write( "\n" ); document.write( "Use Descartes's rule of signs to discuss the possibilities for the roots of the equation. DO NOT solve the equation.\r
\n" ); document.write( "\n" ); document.write( "4x^3-9x^2+6x+4=0\r
\n" ); document.write( "\n" ); document.write( "Thanks again:) \n" ); document.write( "

Algebra.Com's Answer #99113 by vleith(2983) $\"\"$ $\"About$

You can put this solution on YOUR website!
Here is a great description of the rule --> http://www.purplemath.com/modules/drofsign.htm\r
\n" ); document.write( "\n" ); document.write( "Using that information. we see that if x is positive, $\"4x%5E3-9x%5E2%2B6x%2B4=0\"$ has 2 changes in sign. So there are either 2 or 0 real roots.\r
\n" ); document.write( "\n" ); document.write( "If x is negative, $\"4x%5E3-9x%5E2%2B6x%2B4=0\"$ becomes $\"-4x%5E3-9x%5E2-6x%2B4=0\"$ , which has one change in sign. So there is exactly one negative real root.\r
\n" ); document.write( "\n" ); document.write( "does this help ? \n" ); document.write( "

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