document.write( "Question 135287This question is from textbook Basic Technical Mathematics with Calculus
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document.write( ": If one riveter can do a job in 12 days, and a second riveter can do it in 16 days, how long would it take them to do it together? \n" );
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Algebra.Com's Answer #99106 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! Let x=amount of time needed for both working together \n" ); document.write( "One riviter works at the rate of 1/12 job per day\r \n" ); document.write( "\n" ); document.write( "The second riviter works at the rate of 1/16 job per day\r \n" ); document.write( "\n" ); document.write( "Together they work at the rate of 1/12 + 1/16 job per day, or\r \n" ); document.write( "\n" ); document.write( "4/48 + 3/48 = 7/48 of the job per day. So our equation to solve is:\r \n" ); document.write( "\n" ); document.write( "(7/48)x=1 (1 job, that is) multiply each side by 48\r \n" ); document.write( "\n" ); document.write( "7x=48 divide both sides by 7\r \n" ); document.write( "\n" ); document.write( "x=6 6/7 days or 6.8571 days\r \n" ); document.write( "\n" ); document.write( "Hope this helps -----ptaylor \n" ); document.write( " |