document.write( "Question 135287This question is from textbook Basic Technical Mathematics with Calculus
\n" ); document.write( ": If one riveter can do a job in 12 days, and a second riveter can do it in 16 days, how long would it take them to do it together? \n" ); document.write( "

Algebra.Com's Answer #99105 by solver91311(24713) $\"\"$ $\"About$

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If the first guy can do the job in 12 days, then he can do $\"1%2F12\"$ of the job in 1 day. Likewise, the other guy can do $\"1%2F16\"$ of the job in 1 day.\r
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\n" ); document.write( "\n" ); document.write( "Together, they can do $\"1%2F12%2B1%2F16\"$ of the job in 1 day. Which means that they will take $\"1%2F%281%2F12%2B1%2F16%29\"$ days to do the whole job. Just add the two fractions and turn the result over (switch numerator and denominator) to do the arithmetic.\r
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\n" ); document.write( "\n" ); document.write( "Hint: 12 = 2 X 2 X 3 and 16 = 2 X 2 X 2 X 2, so 2 X 2 X 2 X 2 X 3 is your lowest common denominator.\r
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