document.write( "Question 135224: Rationalize the denominator:
\n" ); document.write( "8 - radical 2 divided by 6 - 3 square root 2
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Algebra.Com's Answer #99057 by solver91311(24713)\"\" \"About 
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\"%288-sqrt%282%29%29%2F%286-3sqrt%282%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "The trick is to multiply the fraction by 1 in the form of the conjugate of the denominator divided by itself.\r
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\n" ); document.write( "\n" ); document.write( "If you have an expression of the form \"a%2Bb%2Asqrt%28c%29\", then its conjugate is \"a-b%2Asqrt%28c%29\", and vice versa of course.\r
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\n" ); document.write( "\n" ); document.write( "Here your denominator expression is \"6-3sqrt%282%29\", so the conjugate is \"6%2B3sqrt%282%29\", so you need to multiply your original fraction by 1 in the form of \"%286%2B3sqrt%282%29%29%2F%286%2B3sqrt%282%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "Notice that multiplying a binomial times its conjugate is the reverse of factoring the difference of two squares -- so the result is the first term squared minus the second term squared. Just use FOIL on the numerator expressions:\r
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\n" ); document.write( "\n" ); document.write( "The result is a fraction with a rational number in the denominator, hence the name of the process.
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