document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=135178>Question 135178</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the sum of a geometric series for which a1 = 48, an = 3, and r = -1/2: * </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #99016 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=99016\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the sum of a geometric series for which a(1) = 48, an = 3, and r = -1/2<BR>\n" );
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document.write( "If a(n) = 3<BR>\n" );
document.write( "3 = 48(-1/2)^(n-1)<BR>\n" );
document.write( "3/48 = (-1/2)^(n-1)<BR>\n" );
document.write( "1/16 = (-1/2)^(n-1)<BR>\n" );
document.write( "n-1 = 4<BR>\n" );
document.write( "n = 5<BR>\n" );
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document.write( "S(5) = 48[(-1/2)^5-1]/[(-1/2)-1]<BR>\n" );
document.write( "S(5) = 48[(-33/32)]/[(-3/2)]<BR>\n" );
document.write( "S(5) = 48[11/16]<BR>\n" );
document.write( "S(5) = 33<BR>\n" );
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document.write( "48+(-24)+12+(-6)+3 = 63-30 = 33<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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