document.write( "Question 135199: If Steven can mix 20 drinks in 5 minutes, Sue can mix 20 drinks in 10 minutes, and Jack can mix 20 drinks in 15 minutes, how much time will it take all 3 of them working together to mix the 20 drinks?
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Algebra.Com's Answer #99015 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
Let x=amount of time it takes all three working together to mix 20 drinks
\n" ); document.write( "Steven mixes at the rate of 1/5 of the job ( mixing 20 drinks) per minute
\n" ); document.write( "Sue mixes at the rate of 1/10 of the job per minute
\n" ); document.write( "Jack mixes at the rate of 1/15 of the job per minute\r
\n" ); document.write( "\n" ); document.write( "Together they mix at the rate of 1/5 + 1/10 + 1/15 multiply each term by 30/30\r
\n" ); document.write( "\n" ); document.write( "6/30 + 3/30 +2/30=11/30 \r
\n" ); document.write( "\n" ); document.write( "So, together they mix at the rate of 11/30 of the job per minute. Our equation to solve then is:\r
\n" ); document.write( "\n" ); document.write( "(11/30)x=1 (1 job or 20 drinks, that is)
\n" ); document.write( "multiply each side by 30\r
\n" ); document.write( "\n" ); document.write( "11x=30 divide each side by 11\r
\n" ); document.write( "\n" ); document.write( "x=2.727272727--- minutes\r
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\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor
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