document.write( "Question 135168: okay i have two problems\r
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document.write( "2^(2/3x+1)-3x2^(1/3x)-20=0 \r
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document.write( "also,\r
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document.write( "2^2x-1 -3x2^x-1 +1=0\r
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document.write( "help, please. \n" );
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Algebra.Com's Answer #99003 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 2^[(2/3)x+1)-3[2^(1/3x)]-20=0 \r \n" ); document.write( "\n" ); document.write( "2[2^(x/3)^2] - 3[2(x/3)] - 20 = 0\r \n" ); document.write( "\n" ); document.write( "Let 2^(x/3) = w\r \n" ); document.write( "\n" ); document.write( "2w^2 -3w -20 = 0\r \n" ); document.write( "\n" ); document.write( "(w-4)(2w-5) = 0\r \n" ); document.write( "\n" ); document.write( "w = 4 or w = 5/2 \n" ); document.write( "--------------------- \n" ); document.write( "Therefore: \n" ); document.write( "2^(x/3) = 4 or 2^(x/3) = 5/2\r \n" ); document.write( "\n" ); document.write( "2^(x/3) = 2^2 or (x/3)log2 = log(5/2)\r \n" ); document.write( "\n" ); document.write( "x/3 = 2 or (x/3) = [log(5/2)]/[log2] \n" ); document.write( "x = 6 or x = 3[0.9193] = 2.7580 \n" ); document.write( "====================================\r \n" ); document.write( "\n" ); document.write( "also, \n" ); document.write( "2^2x-1 -3x2^x-1 +1=0 \n" ); document.write( "(1/2)(2^x)^2 - (3/2)(2^x) +1 = 0 \n" ); document.write( "Let 2^x = w \n" ); document.write( "(1/2)w^2 -(3/2)w + 1 = 0 \n" ); document.write( "w^2 - 3w + 2 = 0 \n" ); document.write( "(w-1)(w-2) = 0 \n" ); document.write( "w = 1 or w = 2 \n" ); document.write( "------------------ \n" ); document.write( "2^x = 1 or 2^x = 2 \n" ); document.write( "x = 0 or x = 1 \n" ); document.write( "====================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |