document.write( "Question 20553: Separate 45 into two parts such that 5 times the smaller is 6 less than twice the larger \n" ); document.write( "
Algebra.Com's Answer #9900 by Earlsdon(6294)\"\" \"About 
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Let x be the smaller part of 45.\r
\n" ); document.write( "\n" ); document.write( "\"5x+=+2%2845-x%29+-+6\" Simplify and solve for x.
\n" ); document.write( "\"5x+=+90+-+2x+-+6\" Add 2x to both sides of the equation.
\n" ); document.write( "\"7x+=+84\" Divide both sides by 7.
\n" ); document.write( "\"x+=+12\"\r
\n" ); document.write( "\n" ); document.write( "The smaller part is 12 and the larger part is 45-12 = 33.
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